Question:
Two glass bulbs $A$ and $B$ are connected by a very small tube having a stop-cock. Bulb $A$ has a volume of $100\, cm^3$ and contained the gas while bulb $B$ was empty. On opening stop-clock, the pressure fell down to $40\%$. The volume of the bulb $B$ must be
Two glass bulbs $A$ and $B$ are connected by a very small tube having a stop-cock. Bulb $A$ has a volume of $100\, cm^3$ and contained the gas while bulb $B$ was empty. On opening stop-clock, the pressure fell down to $40\%$. The volume of the bulb $B$ must be
Updated On: Jan 30, 2025
- $75\, cm^3$
- $125\, cm^3$
- $150\, cm^3$
- $250\, cm^3$
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The Correct Option is C
Solution and Explanation
$\therefore 100 � p = V_{2} � \frac{40P}{100}$
$V_{2} = 250\, cc$ (Total volume)
Volume of bulb $B = 250 - 100 = 150\, cc$
$V_{2} = 250\, cc$ (Total volume)
Volume of bulb $B = 250 - 100 = 150\, cc$
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Concepts Used:
Gas Laws
The gas laws were developed at the end of the 18th century, when scientists began to realize that relationships between pressure, volume and temperature of a sample of gas could be obtained which would hold to approximation for all gases.
The five gas laws are:
- Boyle’s Law, which provides a relationship between the pressure and the volume of a gas.
- Charles’s Law, which provides a relationship between the volume occupied by a gas and the absolute temperature.
- Gay-Lussac’s Law, which provides a relationship between the pressure exerted by a gas on the walls of its container and the absolute temperature associated with the gas.
- Avogadro’s Law, which provides a relationship between the volume occupied by a gas and the amount of gaseous substance.
- The Combined Gas Law (or the Ideal Gas Law), which can be obtained by combining the four laws listed above.