Given :
\(\lambda=\frac{h}{mv}\)
Now, \(\frac{\lambda_2}{\lambda_1}=\frac{m_1v_1}{m_2v_2}=\frac{4}{1}\)
\(=\frac{9\times v_2}{1\times v_1}\)
\(\frac{v_2}{1}=\frac{9}{4}\)
K. E = 12 mv2
Now, Ratio of K.E is :
\(\frac{K.E_1}{K.E_2}=\frac{16}{9}\)
So, the correct option is (D) : 16 : 9.