Question:
Two fair dice are thrown. The probability that the number of times the first dice exceeds 3 and that the second exceeds 4 will be:
Two fair dice are thrown. The probability that the number of times the first dice exceeds 3 and that the second exceeds 4 will be:
Updated On: Mar 22, 2024
- \(\frac{2}{6}\)
- \(\frac{5}{6}\)
- \(\frac{1}{6}\)
- \(\frac{3}{6}\)
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The Correct Option is C
Solution and Explanation
The correct answer is (C): \(\frac{1}{6}\)
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