Question

Two fair dice are thrown. The probability that the number of times the dice exceeds 3 and that the second exceeds 4 will be

• A. $\frac{2}{6}$
• B. $\frac{5}{6}$
• C. $\frac{1}{6}$
• D. $\frac{3}{6}$

Answer 1

The Correct Option is C

The correct option is(C): $\frac{1}{6}$