Question:

Two dice are thrown simultaneously. If $X$ denotes the number of fours, then the expectation of $X$ will be:

Updated On: Feb 26, 2025
  • $\frac{5}{9}$
  • $\frac{1}{3}$
  • $\frac{4}{7}$
  • $\frac{3}{8}$
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The Correct Option is B

Solution and Explanation

Each die has a probability of \( \frac{1}{6} \) of showing a four. The expectation of \( X \) (the number of fours) is the sum of the expectations for each die:

\[ E(X) = E(X_1) + E(X_2), \]

where:

\[ E(X_1) = \frac{1}{6}, \quad E(X_2) = \frac{1}{6}. \]

Thus:

\[ E(X) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}. \]

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