Two cars P and Q are travelling on a straight path and are 60 m apart as shown in the figure; Car P is moving with a constant velocity of 36 kmph, while car Q is moving at a constant velocity of 18 kmph. At this instant, the driver in car P applies the brake and collision occurs with car Q after 30 seconds. Assuming uniform deceleration due to braking, which one of the following is the CORRECT velocity (in m/s) of the car P just before the collision?
Step 1: First, convert the velocities from km/h to m/s: \[ {Velocity of car P:} \, 36 \, {km/h} = \frac{36 \times 1000}{3600} = 10 \, {m/s} \] \[ {Velocity of car Q:} \, 18 \, {km/h} = \frac{18 \times 1000}{3600} = 5 \, {m/s} \] Step 2: The relative velocity between car P and car Q is: \[ {Relative velocity} = 10 \, {m/s} - 5 \, {m/s} = 5 \, {m/s} \] Step 3: The cars are 60 meters apart. To find the time to collision, use the formula for relative motion: \[ {Time to collision} = \frac{{Distance}}{{Relative velocity}} = \frac{60}{5} = 12 \, {seconds} \] Step 4: Since the collision occurs after 30 seconds, this suggests that car P applies the brake at the moment when it is 60 meters away from car Q. The car P would be decelerating during this 30-second period. The velocity of car P just before the collision can be found using the equation of motion under uniform deceleration: \[ v = u + at \] where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration (negative for deceleration), and \( t \) is the time.
Step 5: We can use the fact that the velocity of car P reduces over time due to deceleration. Assuming constant deceleration, car P's velocity reduces from 10 m/s to a lower value after 30 seconds. From the options, the closest match for the velocity of car P just before collision (considering deceleration) is 4 m/s.
Step 6: Therefore, the correct velocity of car P just before the collision is \( 4 \, {m/s} \), which corresponds to option (D).
The figure shows a rod PQ, hinged at P, rotating counter-clockwise with a uniform angular speed of 15 rad/s. A block R translates along a slot cut out in rod PQ. At the instant shown the distance \( PR = 0.5 \, {m} \) and \( \theta = 60^\circ \). The relative velocity of R with respect to the rod PQ is 5 m/s at the instant shown. The relative acceleration of R with respect to the rod PQ is zero at the instant shown.
Which one of the following is the CORRECT magnitude of the absolute acceleration (in m/s\(^2\)) of block R?
Consider two blocks, P of mass 100 kg and Q of mass 150 kg, resting as shown in the figure. The angle \( \theta = 30^\circ \). The coefficient of friction between the two blocks is 0.2. Assume no friction exists at all other interfaces. The minimum force required to move the block P upward is \( W \). Which one of the following options is closest to the CORRECT magnitude of \( W \) (in N)?
A force of \( P = 100 \, {N} \) is applied at the ends of the pliers as shown in the figure. Neglecting friction, the force exerted by the upper jaw on the workpiece is ........... N (in integer).
Consider a beam with a square box cross-section as shown in the figure. The outer square has a length of 10 mm. The thickness of the section is 1 mm. The area moment of inertia about the x-axis is ........... mm\(^4\) (in integer).
In the figures given below, L and H indicate low and high pressure centers, respectively; PGF, CoF and CeF indicate Pressure Gradient Force, Coriolis Force and Centrifugal Force, respectively; \( V \) is Velocity. [The arrows indicate only the directions but not the magnitudes of the forces and velocity.]
Which of the following is/are the correct representation(s) of the directions of various forces and velocity in the gradient wind balance in the northern hemisphere?
Which of the following is the correct form of the mass divergence form of the continuity equation for a compressible fluid? [In the given equations, \( \rho \) is the density and \( \nabla \) the three-dimensional velocity vector of the fluid.]
[(i)] $\displaystyle \frac{\partial \rho}{\partial t} + \nabla \times (\rho \mathbf{v}) = 0$
[(ii)] $\displaystyle \frac{\partial \rho}{\partial t} + \nabla \cdot (\rho \mathbf{v}) = 0$
[(iii)] $\displaystyle \frac{\partial \mathbf{v}}{\partial t} + \rho \cdot \nabla \mathbf{v} = 0$
[(iv)] $\displaystyle \frac{\partial \rho}{\partial t} + \mathbf{v} \cdot \nabla \rho = 0$
The vertical (depth) profiles for three parameters P1, P2, and P3 in the northern Indian Ocean are given in the figure below. The values along the x-axis are the normalized values of the parameters and y-axis is the depth (m).
Identify the parameters P1, P2, and P3 from the options given below.