Two bodies of mass $4\,kg$ and $6\,kg$ are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is :

The acceleration of the system $a=\frac{\left(m_{2}-m_{1}\right)g}{m_{1}+m_{2}}$ where $m_{1}>\,m_{2}$ $a=\frac{(6-4)g}{6+4}$ $=\frac{2g}{10}$ $a=\frac{g}{5}$

Two bodies of mass 4kg and 6kg are tied to the ends of a massless string.

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Concepts Used:

Newtons Laws of Motion

Newton’s First Law of Motion:

Newton’s 1^st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion:

Newton’s 2^nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.

Mathematically, we express the second law of motion as follows:

Newton’s Third Law of Motion:

Newton’s 3^rd law states that there is an equal and opposite reaction for every action.

List-I (Conversion)		List-II (Shape/geometry)
(A)	1 mol of H₂O to O₂	(I)	3F
(B)	1 mol of MnO^-₄ to Mn²⁺	(II)	2F
(C)	1.5 mol of Ca from molten CaCl₂	(III)	1F
(D)	1 mol of FeO to Fe₂O₃	(IV)	5F