Let the force applied on A be \( F = 100 \, \text{N} \), and the masses of A and B be \( m_A = 7 \, \text{kg} \) and \( m_B = 3 \, \text{kg} \), respectively.
The total mass of the system is:
\[
m_{\text{total}} = m_A + m_B = 7 \, \text{kg} + 3 \, \text{kg} = 10 \, \text{kg}
\]
Now, the acceleration of the system is given by:
\[
a = \frac{F}{m_{\text{total}}} = \frac{100}{10} = 10 \, \text{m/s}^2
\]
The force on A, which is exerted on B, can be calculated using Newton's second law for the body B:
\[
F_B = m_B \times a = 3 \times 10 = 30 \, \text{N}
\]
Thus, the force on A applied to B is \( 30 \, \text{N} \).