Question:
Two blocks of masses $2.9\, kg$ and $1.9 \,kg$ are suspended from a rigid support $S$ by two inextensible wires each of length $1 \,m$ (figure). The upper wire has negligible mass and the lower wire has a uniform mass of $0.2\, kg/m$. The whole system of blocks, wires and support have an upward accelration of $ 0.2\,m/s^{2} $ . The tension at the mid-point of the upper wire is
Two blocks of masses $2.9\, kg$ and $1.9 \,kg$ are suspended from a rigid support $S$ by two inextensible wires each of length $1 \,m$ (figure). The upper wire has negligible mass and the lower wire has a uniform mass of $0.2\, kg/m$. The whole system of blocks, wires and support have an upward accelration of $ 0.2\,m/s^{2} $ . The tension at the mid-point of the upper wire is
Updated On: Aug 1, 2022
- 20 N
- 30 N
- 40 N
- 50 N
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The tension at $A =\left(m_{1}+m_{2}\right)(g+a)$
$=(2.9+1.9)(9.8+2)=50\, N$
Was this answer helpful?
0
0
Top Questions on tension
A body of mass 1kg is suspended with the help of two strings making angles as shown in the figure. Magnitude of tensions $ T_1 $ and $ T_2 $, respectively, are (in N):
- Tension of a rope when a man of mass \( m \) climbs up or down with an acceleration \( a<g \)?
- In a vertical circle of radius r, at what point in its path does a particle have tension equal to zero if it is just able to complete the vertical circle?
- A bob is whirled in a horizontal plane by means of a string with an initial speed of ω rpm. The tension in the string is T. If speed becomes 2ω while keeping the same radius, the tension in the string becomes:
- If the length of a string is \(P\) when the tension in it is 6 N and its length is \(Q\) when the tension in it is 8 N, then the original length of the string is:
View More Questions
Concepts Used:
Tension
A force working along the length of a medium, especially if this force is carried by a flexible medium like cable or rope is called tension. The flexible cords which bear muscle forces to other parts of the body are called tendons.
Net force = 𝐹𝑛𝑒𝑡 = 𝑇−𝑊=0,
where,
T and W are the magnitudes of the tension and weight and their signs indicate a direction, be up-front positive here.
Read More: Tension Formula