Question:

A bob is whirled in a horizontal plane by means of a string with an initial speed of ω rpm. The tension in the string is T. If speed becomes 2ω while keeping the same radius, the tension in the string becomes:

Updated On: Dec 4, 2024
  • T
  • 4T
  • \(\frac{T}{4}\)
  • √2T
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The Correct Option is B

Solution and Explanation

Tension in the string is proportional to the square of the velocity:
$T \propto v^2$.
If $v \to 2v$, then $T \to 4T$.

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