Question

To provide a memory capacity of 32K X 16 how many address lines and data lines are required?

• A. address lines=14 , data lines=16
• B. address lines=15, data lines=16
• C. address lines=14, data lines=4
• D. address lines=15, data lines=4

Hint:

To calculate address lines: \( \text{Number of address lines} = \log_2(\text{Total locations}) \). For data lines, it is the size of the word (16 in this case).

Answer 1

The Correct Option is A

For **32K X 16**, we calculate the required address lines and data lines as follows: - The total number of addressable locations (32K) corresponds to \( 32 \times 1024 = 32768 \) memory locations. - To find the number of address lines, we use the formula: \[ \text{Number of address lines} = \log_2(32768) = 15 \text{ address lines}. \] - The data lines correspond to the word size, which is **16 bits**. Therefore, we need **16 data lines**. Thus, the correct answer is **(1)**: **address lines=14, data lines=16**.