Question:

To neutralize completely 20 mL of 0.1M aqueous solution of phosphorus acid $(H_3PO_3)$ the volumeof 0.1 M aqueous KOH solution required is

Updated On: Jun 23, 2023
  • 10 mL
  • 20 mL
  • 40 mL
  • 60 mL
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The Correct Option is C

Solution and Explanation

$H_3PO_3$ is a dibasic acid. $ {H_3PO_3 + 2 KOH -> K_2HPO_3 + 2H_2O}$ $\frac{M_AV_A}{n_A} = \frac{M_BV_B}{n_B}$ $\frac{0.1 \times 20}{1} = \frac{0.1 \times V_B}{2}$ $V_B$ = 40 mL.
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.