To eliminate the 5th harmonic voltage from the phase voltage of an alternator, the coils should be short-pitched by an electrical angle of:
Step 1: In alternators, short-pitching (chorded winding) is applied to reduce harmonics, especially the 3rd, 5th, and 7th harmonics.
Step 2: The required short-pitching angle (\(\alpha\)) to eliminate a specific harmonic is calculated as: \[ \alpha = \frac{180^\circ}{\text{Harmonic Number}} \] For the 5th harmonic: \[ \alpha = \frac{180^\circ}{5} = 36^\circ \]
Step 3: Therefore, to remove the 5th harmonic voltage, the coils must be short pitched by 36 degrees.
Match the LIST-I with LIST-II
| LIST-I (Logic Gates) | LIST-II (Expressions) | ||
|---|---|---|---|
| A. | EX-OR | I. | \( A\bar{B} + \bar{A}B \) |
| B. | NAND | II. | \( A + B \) |
| C. | OR | III. | \( AB \) |
| D. | EX-NOR | IV. | \( \bar{A}\bar{B} + AB \) |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Counters) | List-II (Delay/Number of States) |
|---|---|
| (A) n-bit ring counter | (I) Number of states is \( 2^n \) |
| (B) MOD-\(2^n\) asynchronous counter | (II) Fastest counter |
| (C) n-bit Johnson counter | (III) Number of used states is \( n \) |
| (D) Synchronous counter | (IV) Number of used states is \( 2n \) |
Choose the correct answer from the options given below:
A MOD 2 and a MOD 5 up-counter when cascaded together results in a MOD ______ counter.