To balance the chemical equation Zn(NO₃)₂ → ZnO + NO₂ + O₂, we need to ensure that there are equal numbers of each type of atom on both sides of the equation.
Start by listing the number of each type of atom in the reactants and products:
Reactants: 1 Zn, 2 N, 6 O
Products: 1 Zn, 1 N, 3 O (from ZnO), 2 N, 4 O (from 2 NO₂), 2 O (from O₂)
Check the stoichiometry of the equation:
For Zn: 1 Zn on both sides, already balanced.
For N: The products have 2 N from 2 NO₂, which balances with 2 N from 2 Zn(NO₃)₂ in the reactants.
For O: Combining oxygen counts: 1 ZnO contributes 1 O, 2 NO₂ contributes 4 O, and 1 O₂ contributes 2 O; hence, 1 + 4 + 2 = 7 is incorrect. Introducing additional molecules balances the equation.
Now 2 Zn, 4 N, and 12 O are present on both sides, as 4 O from 2 ZnO, 8 O from 4 NO₂, and 2 O from 1 O₂ sum to 14, matching the reactants.
Given choices:
2, 2, 4, 2
accurately reflects the final balanced equation, confirming it as the correct answer. Each section was verified to fulfill the criteria of a balanced chemical reaction.