Question:
Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in
Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in
Updated On: Aug 1, 2022
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Electric lines of force never form a closed loop.
Was this answer helpful?
0
0
Top Questions on Electric Field
- \(\sigma\) is the uniform surface charge density of a thin spherical shell of radius \(R\). The electric field at any point on the surface of the spherical shell is:
- JEE Main - 2024
- Physics
- Electric Field
- The distance between charges \(+q\) and \(-q\) is \(2l\) and between \(+2q\) and \(-2q\) is \(4l\). The electrostatic potential at point \(P\) at a distance \(r\) from center \(O\) is \(-\alpha \left[\frac{q}{r^2}\right] \times 10^9 \, \text{V}\), where the value of \(\alpha\) is ______.
(Use \(\frac{1}{4 \pi \epsilon_0} = 9 \times 10^9 \, \text{Nm}^2 \text{C}^{-2}\))
- JEE Main - 2024
- Physics
- Electric Field
- 1 tesla =
- AP POLYCET - 2024
- Physics
- Electric Field
- A thin glass rod is bent in a semicircle of radius R.A charge is non-uniformly distributed along the rod with a linear charge density \(\lambda=\lambda_0sin\theta\) (\(\lambda_0\) is a positive constant). The electric field at the center P of the semicircle is
- WBJEE - 2023
- Physics
- Electric Field
- When electric field is applied to the electrons in a conductor it starts
- JEE Main - 2023
- Physics
- Electric Field
View More Questions
Questions Asked in IIT JEE exam
- If the weight of an object on earth's surface is 400 N, then weight of the same particle at a depth \(\frac{R}{2}\) from surface would be (R is radius of earth)
- IIT JEE - 2023
- Stereoisomers
- For an electron and a proton (mp=1847 me) with same de-broglie wavelength, the ratio of linear momentum is equal to?
- IIT JEE - 2023
- Stereoisomers
- The major product of the following reaction is
- IIT JEE - 2022
- Hydrocarbons
- Let $ \alpha ( a) \, and \, \beta (a) $ be the roots of the equation $ (\sqrt [3] {1 + a} - 1) x^2 - (\sqrt {1 + a} - 1) x + (\sqrt [ 6] {1 + a} - 1) = 0$, where a > - 1. Then, $ lim_{a \to 0^+ } $, $ \alpha (a) \, and \, lim_{a \to 0^+ } \beta $ (a) are
- IIT JEE - 2012
- Quadratic Equations
- Let $f:(-1,1)\rightarrow$ R be such that $f(cos 4 \theta)=\frac{2}{2-sec^2 \theta}$ for $\theta \in \Bigg(0,\frac{\pi}{4}\Bigg)\cup\Bigg(\frac{\pi}{4},\frac{\pi}{2}\Bigg).$ Then, the value(s) of $f\Bigg(\frac{1}{3}\Bigg)$ is are
- IIT JEE - 2012
- Functions
View More Questions
Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).