Question

Three pipes A, B and C can fill a tank in 20 min, 10 min and 30 min respectively. When the tank is empty, all the three pipes are opened. A, B, C discharge chemical solutions 'x', 'y', 'z' respectively. The proportion of solution 'y' in the liquid in the tank after 3 min is

• A. \(\frac{6}{11}\)
• B. \(\frac{8}{11}\)
• C. \(\frac{7}{11}\)
• D. \(\frac{5}{11}\)

Answer 1

The Correct Option is A

Filling done by all 3 pipes in 3 minutes \(=\frac{3}{20}+\frac{3}{10}+\frac{3}{30}=\frac{11}{20}\)
Filling done by 2nd pipe in 3 minutes \(=\frac{3}{10}\)
So, required ratio \(=\frac{\frac{3}{10}}{\frac{11}{20}}=\frac{6}{11}\)
The correct option is (A)