Assume one machine completes 1 unit of work per day.
Given that two machines together complete the job in 13 days, the total work is:
\[ \text{Work} = 2 \times 1 \times 13 = 26 \text{ units} \]
Let the daily work output of one man be denoted by \( m \).
We are told: \[ 3m + 8 \times 1 = 2(8m + 3 \times 1) \]
Solving: \[ 3m + 8 = 16m + 6 \Rightarrow 3m - 16m = 6 - 8 \Rightarrow -13m = -2 \Rightarrow m = \frac{2}{13} \]
Now, let \( x \) be the number of men required to complete 26 units of work in 13 days. Then, using the formula:
\[ x \cdot m \cdot 13 = 26 \Rightarrow x \cdot \frac{2}{13} \cdot 13 = 26 \Rightarrow x \cdot 2 = 26 \Rightarrow x = 13 \]
\[ \boxed{13 \text{ men}} \]