Three identical spheres, each of mass $M$, are placed at the corners of a right angle triangle with mutually perpendicular sides equal to $2\,m$ (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass
- $2\left(\hat{i}+\hat{j}\right)$
- $\left(\hat{i}+\hat{j}\right)$
- $\frac{2}{3}\left(\hat{i}+\hat{j}\right)$
- $\frac{4}{3}\left(\hat{i}+\hat{j}\right)$
The Correct Option is C
Solution and Explanation
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Concepts Used:
Center of Mass
The center of mass of a body or system of a particle is defined as a point where the whole of the mass of the body or all the masses of a set of particles appeared to be concentrated.
The formula for the Centre of Mass:
Center of Gravity
The imaginary point through which on an object or a system, the force of Gravity is acted upon is known as the Centre of Gravity of that system. Usually, it is assumed while doing mechanical problems that the gravitational field is uniform which means that the Centre of Gravity and the Centre of Mass is at the same position.