Step 1: Problem Setup.
We are tasked with finding the number of unique circular arrangements of 5 units, out of which 2 are alike (\( E \) and \( E \)).
Step 2: Formula for circular arrangements.
The total number of arrangements in a circle, accounting for repetition, is given by:
\[
\frac{(n-1)!}{k!},
\]
where \( n \) is the total number of units and \( k \) is the number of identical units.
Step 3: Substituting the values.
Here, \( n = 5 \) and \( k = 2 \) (for \( E \) and \( E \)):
\[
Number of unique arrangements} = \frac{(5-1)!}{2!}.
\]
Step 4: Simplifying the factorials.
\[
Number of unique arrangements} = \frac{4!}{2!} = \frac{4 \times 3 \times 2 \times 1}{2 \times 1}.
\]
Step 5: Calculating the result.
\[
Number of unique arrangements} = 12.
\]