Each pair of twins must sit together. Since we are seating twins next to each other, treat each pair as a single unit initially. There are three pairs of twins, and each pair has 2 permutations (since each twin can sit on either side of the other).
Step 1: Arrangement of units.
In a circular arrangement, fix one pair and arrange the remaining two pairs around it. The number of ways to arrange two pairs around the fixed one is \((2-1)!\).
Therefore, there are 1 way to arrange the pairs relative to each other.
Step 2: Arranging twins within each pair.
Each pair of twins can be arranged in 2! = 2 ways.
Since there are three pairs, the total permutations within the pairs are \(2^3 = 8\).
Total arrangements:
The total number of unique seating arrangements is the product of the arrangements of pairs and the permutations within pairs:
\[
1 \times 8 = 8
\]
Correction on total due to symmetry:
The previous calculation does not account for the fact that the circular table allows for rotations that do not change relative positions, reducing the unique arrangements.
With one pair fixed, consider rotating the starting position of the first twin. The remaining pairs can be arranged in \(2 \times 3\) ways, since the first twin's position breaks the circular symmetry.
\[
2 \times 6 = 12
\]
Thus, there are 12 unique seating arrangements possible.