Question:
Three containers of the same volume contain three different gases. The masses of the molecules are $m_1, m_2$ and $m_3$ and the number of molecules in their respective containers are $N_1, N_2$ and $N_3$. The gas pressure in the containers are $P_1, P_2$ and $P_3$ respectively. All the gases are now mixed and put in one of these containers. The pressure P of the mixture will be
Three containers of the same volume contain three different gases. The masses of the molecules are $m_1, m_2$ and $m_3$ and the number of molecules in their respective containers are $N_1, N_2$ and $N_3$. The gas pressure in the containers are $P_1, P_2$ and $P_3$ respectively. All the gases are now mixed and put in one of these containers. The pressure P of the mixture will be
Updated On: Jul 7, 2022
- $P < (P_1 + P_2 + P_3)$
- $P = \frac{P_1 + P_2 + P_3}{3}$
- $ P = P_1 + P_2 + P_3$
- $ P > (P_1 + P_2 + P_3)$
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The Correct Option is C
Solution and Explanation
According to Dalton?? law of partial pressures, we have $P = P_1 + P_2 + P_3 $
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