\[ \text{Area} = \int_{0}^{\pi} \sin(x) \, dx \]
The integral of \(\sin(x)\) is \(-\cos(x)\). Evaluating the definite integral:
\[ \text{Area} = [-\cos(x)]_{0}^{\pi} = (-\cos(\pi)) - (-\cos(0)) \]
We know that \(\cos(\pi) = -1\) and \(\cos(0) = 1\). Substituting these values:
\[ \text{Area} = (-(-1)) - (-1) = 1 - (-1) = 1 + 1 = 2 \]
The calculated area matches option (C).
The closest value representing the area of the shaded curve is 2.
The yellow shaded region appears to be under a symmetric curve from \( x = 0 \) to \( x = 3 \), with a maximum height of \( y = 1 \). We approximate this region using a sine curve:
Assume the curve is \( y = \sin\left(\frac{\pi x}{3}\right) \). The area under this curve from \( x = 0 \) to \( x = 3 \) is:
\[ \int_0^3 \sin\left(\frac{\pi x}{3}\right)\, dx = -\frac{3}{\pi} \cos\left(\frac{\pi x}{3}\right) \Big|_0^3 \] \[ = -\frac{3}{\pi} \left[\cos(\pi) - \cos(0)\right] = -\frac{3}{\pi} \left[-1 - 1\right] = \frac{6}{\pi} \approx 1.91 \]
Therefore, the area is approximately 1.91, which is closest to option (C) 2.