There are two identical vessels X and Y. Y is filled with water to the brim and X is empty. There are two pails A and B, such that B can hold half as much water as A. One operation is said to be executed when water is transferred from Y to X using B once. If A can hold $\frac{1}{2}$ a litre of water and it takes 40 operations to equate the water level in X and Y, what is the total volume of water in the system ?

Question

There are two identical vessels X and Y. Y is filled with water to the brim and X is empty. There are two pails A and B, such that B can hold half as much water as A. One operation is said to be executed when water is transferred from Y to X using B once. If A can hold  $\frac{1}{2}$  a litre of water and it takes 40 operations to equate the water level in X and Y, what is the total volume of water in the system ?

cdquestions Admin · Accepted Answer

A can hold $\frac{1}{2}$  a litre of water, and B =  $\frac{1}{4}$  litre of water can hold. In the one complete operation, the water transferred will be = 1 - ( $\frac{1}{2}$ ) =  $\frac{1}{2}$  liters as 1 liter goes from Y to X. So 1 liter is contained in X. But  $\frac{1}{2}$  liter goes from X to Y as well. So net  $\frac{1}{2}$  liters remain in X. If it takes 40 operations to equate water level, = 40 × ( $\frac{1}{2}$ ) = 20 liters is contained by both X and Y. So the total volume of water in the system will be 40 litres The correct option is (C)

Answer

<div>20 litres</div>

Answer

<div>10 litres</div>

Answer

<div>40 litres</div>

Answer

20$\frac{3}{4}$

The Correct Option is C

Solution and Explanation

Top Questions on Mensuration

Questions Asked in MAT exam