Question:
There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio
There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio
Updated On: Sep 30, 2024
- 229 : 141
- 220 : 149
- 239 : 161
- 251 : 163
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The Correct Option is C
Solution and Explanation
The correct answer is (C):
Let the ratio of A and B in drum 2 be x : 1
Applying alligation,
13/20-x/x+1 = 3/4 ⇒ 13/20-x/x+1 = 3/4×72-65/100 = 21/400
⇒ x/25-13/20 = 13/20 - 21/400 = 239/400
⇒ 400x = 239x + 239
x = 239/161
Required ratio is 239 : 161.
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