Question:

There are three persons A B, and C in a room. If a person D joins the room, the average weight of the persons in the room reduces by x kg . Instead of D , if person E joins the room, the average weight of the persons in the room increases by 2 kg x . If the weight of E is 12 kg more than that of D , then the value of x is

Updated On: Jul 21, 2025
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The Correct Option is C

Solution and Explanation

To solve the problem, we start by defining variables: let the total weight of persons A, B, and C be denoted as \( S \) and their average weight as \( \frac{S}{3} \).

If person D joins the group, the new average weight becomes \( \frac{S + w_D}{4} \), where \( w_D \) is the weight of person D. We are told this average is reduced by \( x \) kg: 

\(\frac{S}{3} - x = \frac{S + w_D}{4}\)

Multiplying through by 12 to clear denominators gives:

\(4S - 12x = 3S + 3w_D\)

Simplifying, we get:

\(S = 12x + 3w_D\)

Similarly, if person E joins instead, the average weight increases by \( 2x \) kg:

\(\frac{S}{3} + 2x = \frac{S + w_E}{4}\)

Clearing denominators by multiplying through by 12 yields:

\(4S + 24x = 3S + 3w_E\)

After simplification:

\(S = 24x + 3w_E\)

Equating both expressions for \( S \), we have:

\(12x + 3w_D = 24x + 3w_E\)

Dividing through by 3 to simplify gives:

\(4x + w_D = 8x + w_E\)

Since \( w_E = w_D + 12 \), substitute into the equation:

\(4x + w_D = 8x + w_D + 12\)

Simplify to find \( x \):

\(-4x = 12\)

Solving for \( x \) yields:

\(x = 1\)

Thus, the value of \( x \) is 1.

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