There are three coplanar parallel lines. If any $P$ points are taken on each of the lines, the maximum number of triangles with vertices at these points, is
Updated On: Jul 7, 2022
$^{3P}C_{3}$
$P^{2} \left(P-1\right)$
$P^{2} \left(4P-1\right)$
$P^{2} \left(4P-3\right)$
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The Correct Option isD
Solution and Explanation
Required number of ways
$=\, ^{P}C_{1} \times\, ^{P}C_{1} \times\,^{P}C_{1} + \,^{P}C_{2} \times\,^{2P}C_{1} \times\, ^{3}P_{1}$$ = P^{2}\left(4P-3\right)$.