Question:

There are $5$ letters and $5$ different envelopes. The number of ways in which all the letters can be put in wrong envelope, is

Updated On: Apr 19, 2024
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The Correct Option is B

Solution and Explanation

Required numbers
$=5 !\left[1-\frac{1}{1 !}+\frac{1}{2 !}-\frac{1}{3 !}+\frac{1}{4 !}=\frac{1}{5 !}\right]=44$
if $r(0 \leq r \leq n)$ objects occupy the original places and none of the remaining $(n-r)$ objects occupies its original places then the number of such arrangements $={ }^{n} C_{r}(n-r) !$
$\left[1 \frac{1}{1 !}+\frac{1}{2 !}-\frac{1}{3 !}+\ldots+(-1)^{n-2} \frac{1}{(n-r) !}\right]$
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Concepts Used:

Permutations and Combinations

Permutation:

Permutation is the method or the act of arranging members of a set into an order or a sequence. 

  • In the process of rearranging the numbers, subsets of sets are created to determine all possible arrangement sequences of a single data point. 
  • A permutation is used in many events of daily life. It is used for a list of data where the data order matters.

Combination:

Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.

  • Combination refers to the combination of about n things taken k at a time without any repetition.
  • The combination is used for a group of data where the order of data does not matter.