Question

There are 37 men and 33 women at a party. If a prize is given to one person chosen at random, then the probability that the prize goes to a woman is

• A. \(\frac{33}{70}\)
• B. \(\frac{32}{70}\)
• C. \(\frac{33}{80}\)
• D. \(\frac{37}{70}\)
• E. \(\frac{37}{80}\)

Answer 1

The Correct Option is A

The total number of people at the party is the sum of the number of men and women: \[ \text{Total number of people} = 37 + 33 = 70 \] The number of women is 33. The probability of choosing a woman is the ratio of the number of women to the total number of people: \[ P(\text{woman}) = \frac{33}{70} \]

The correct option is (A) : \(\frac{33}{70}\)

Answer 2

There are 37 men and 33 women at a party. The total number of people is \(37 + 33 = 70\).

The probability that the prize goes to a woman is the number of women divided by the total number of people:

\(P(\text{prize goes to a woman}) = \frac{\text{number of women}}{\text{total number of people}} = \frac{33}{70}\)