Question

There are 2 people R and P, their speed is in the ratio 3:4. R has a head start of 10 m. Who lost and by what distance?

Hint:

Use the time-distance-speed relation to solve such problems.

Answer 1

Step 1: Use the speed ratio.
Let the speed of R be \( 3x \) and the speed of P be \( 4x \). The time taken by both to run the same distance will be the same.
Step 2: Solve for the distance.
Let the distance R runs be \( d \) and P runs \( d + 10 \) meters. Equating the times: \[ \frac{d}{3x} = \frac{d + 10}{4x} \] Solve this equation to find \( d = 30 \). Hence, R lost by 15 meters.