There are $15$ points in a plane, no three of which are in a straight line, except $6$, all of which are in a st. line. The number of st. lines which can be drawn by joining them is
Updated On: Jul 7, 2022
$^{15}C_2-6 $
$^{15}C_2-\,^6C_2 $
$^{15}C_2-\,^6C_2-1 $
$^{15}C_2-\,^6C_2+1 $
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The Correct Option isD
Solution and Explanation
Reqd. no. of st. lines $= ^{15}C_{2}-\,^{6}C_{2}+1$
[$\because$ join of two pts. from a st. line and $6$ pts. which are collinear given only st. line in place of $^{6}c_{2}$]