Question

There are 12 children in a party. For a game they have to be paired up. How many different pairs can be made for the game?

• A. 46
• B. 24
• C. 120
• D. 66
• E. 132

Hint:

“Pair” means choosing 2 without order, so always use combinations \(\binom{n}{2}\).

Answer 1

The Correct Option is D

Step 1: Interpret the problem.
We are making 1 pair out of 12 children.

Step 2: Apply combination.
Choosing 2 children from 12: \[ \binom{12}{2} = \frac{12 \times 11}{2} = 66 \]
Final Answer:
\[ \boxed{66} \]