Step 1: Identify the Yellow and Red-Orange Complexes.
The yellow solution of K\(_2\)CrO\(_4\) contains the dichromate ion (CrO\(_4^{2-}\)), which changes to a red-orange color when HCl is added, forming the chromic ion (Cr\(^{3+}\)) in the presence of chloride.
Step 2: Oxidation States and Color Origin.
The chromate ion (\( \text{Cr}^{6+} \)) is reduced to the chromic ion (\( \text{Cr}^{3+} \)) in the reaction. The color change originates from a charge transfer transition between the metal and the ligand.
Step 3: Conclusion.
The correct answer is the dichromate ion, with an oxidation state of +6 for both chromium and oxygen, and the color change is due to charge transfer.
Final Answer: \[ \text{Dichromate ion, +6 and +6, charge transfer.} \]
The correct orders among the following are:
[A.] Atomic radius : \(B<Al<Ga<In<Tl\)
[B.] Electronegativity : \(Al<Ga<In<Tl<B\)
[C.] Density : \(Tl<In<Ga<Al<B\)
[D.] 1st Ionisation Energy :
In\(<Al<Ga<Tl<B\)
Choose the correct answer from the options given below :