Question:

The x and y coordinates of the particle at any time are $x = 5t - 2t^2$ and $y = 10t$ respectively, where $x$ and $y$ are in meters and t in seconds. The acceleration of the particle at $t = 2s$ is :

Updated On: Jul 18, 2024
  • $5 m/s^2$
  • $-4 \, ms^2$
  • $ -8 \, ms^2$
  • 0
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The Correct Option is B

Solution and Explanation

$x=5 t-2 t^{2} \,\,\, y=10 t$
$\frac{d x}{d t}=5-4 t \,\,\, \frac{d y}{d t}=10$
$v_{x}=5-4 t \,\,\, v_{y}=10$
$\frac{d v}{d t} x=-4 \,\,\, \frac{d v}{d t} y=10$
$a_{x}=-4\,\,\, a_{y}=0$
Acceleration of particle at $t=2 s$ is $=-4 m / s ^{2}$
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Concepts Used:

Acceleration

In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration

acceleration