The work functions for metals A,B and C are respectively 1.92 eV, 2.0 eV and 5 eV. According to Einstein's equation, the metals which will emit photoelectrons for a radiation of wavelength 4100 Å is/are:
none
A only
A and B only
all the three metals
The Correct Option is C
Solution and Explanation
Energy of electron with wavelength of 4100A° is
\(\frac{hc}{\lambda}\) = 4.845x10-19J
= 3.024eV
This incident electron would emit photon from metals whose work potential is less than its energy.
so, it would emit photons from metals A and B.
Therefore, the correct option is (C): A and B only
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Concepts Used:
Dual Nature of Matter
- The concept of Dual Nature of Matter was proposed after various experiments supported both wave as well particle nature of light.
- The particle nature of matter came into the picture when Albert Einstein looked up to the experiment conducted by Max Planck and observed that the wavelength and intensity of matter have a certain impact on the ejected electrons. Experiments such as the photoelectric effect suggested that light has a particle nature, i.e. light travels in form of packets of energy (E = h\(\nu\))
- On the other hand, the wave nature of matter was hypothesised by De-Broglie and confirmed by the Davisson - German experiment.
- Therefore, it’s concluded that matter has dual nature; it means that it has both the properties of a particle as well as a wave.
