Step 1: Understanding the Concept:
The median is the middle value in a dataset that has been arranged in order of magnitude. It divides the dataset into two equal halves.
Step 2: Key Formula or Approach:
1. Arrange the data in ascending or descending order.
2. Count the number of observations, N.
3. If N is odd, the median is the \(\left(\frac{N+1}{2}\right)\)th value.
4. If N is even, the median is the average of the \(\left(\frac{N}{2}\right)\)th and \(\left(\frac{N}{2}+1\right)\)th values.
Step 3: Detailed Calculation:
1. The given dataset is: 7900, 9000, 7800, 8300, 2900, 4545, 5100, 3700, 9900, 4545.
2. Number of observations (N) = 10.
3. Arrange the data in ascending order:
2900, 3700, 4545, 4545, 5100, 7800, 7900, 8300, 9000, 9900
4. Calculate the median: Since N is even (10), the median is the average of the 5th and 6th values.
- 5th value = 5100
- 6th value = 7800
\[ \text{Median} = \frac{5100 + 7800}{2} = \frac{12900}{2} = 6450 \]
Step 4: Final Answer:
The median WBC count of the group is 6450 per mm\(^3\). Therefore, option (D) is correct.