The volume of water to be added to N/2 HCl to prepare $500 cm^3$ of N/10 solution is
- 45 $cm^3$
- 400 $cm^3$
- 450 $cm^3$
- 100 $cm^3$
The Correct Option is B
Solution and Explanation
$\frac{N}{2} \times V_1 = \frac{N}{10} \times 500$
$V_1$ =100
Vol. of N/10 solution = 500 $cm^3$
Vol. of N/2 solution = 100 $cm^3$
$\therefore$ Water to be added = (500 - 100) $cm^3$ = 400 $cm^3$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.