Step 1: Use the dilution equation.
The dilution equation is given by:
\[
C_1 V_1 = C_2 V_2,
\]
where \( C_1 \) and \( C_2 \) are the concentrations of the stock and the final solution, and \( V_1 \) and \( V_2 \) are the volumes of the stock and final solution, respectively.
Step 2: Substituting the known values.
- \( C_1 = 50X \) (concentrated solution)
- \( C_2 = 1X \) (final solution)
- \( V_2 = 350 \, \text{mL} \) (final volume)
\[
50X \times V_1 = 1X \times 350 \, \text{mL},
\]
\[
V_1 = \frac{350}{50} = 7 \, \text{mL}.
\]
Step 3: Conclusion.
The required volume of the concentrated buffer stock solution is \( \boxed{7} \, \text{mL} \).
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 