Question

The voltage time graph of a triangular wave having peak value Vo is as shown in figure.The rms value of V in time interval from t = \(0\) to \(T/4\) is

• A. \(V_0/3\)
• B. \(V_0/2\)
• C. \(V_0/\sqrt2\)
• D. \(V_0/\sqrt3\)

Hint:

Rms of linear ramp = peak/√3.

Answer 1

The Correct Option is D

Step 1: For triangular wave over full period: \[ V_{\text{rms}}=\frac{V_0}{\sqrt3}. \]
Step 2: Any fraction of a linear ramp preserves same rms coefficient because \[ V_{\text{rms}}^2=\frac1{t}\int (k t)^2 dt \Rightarrow \frac{V_0^2}{3}. \] Hence rms \(=V_0/\sqrt3\).