Question:
The voltage of an A.C. source varies with time according to the equation $V=50\, \sin\,100\pi\,t\,\cos\,100\pi\,t$ . Where 't' is the sec and 'V' is in volts. Then
The voltage of an A.C. source varies with time according to the equation $V=50\, \sin\,100\pi\,t\,\cos\,100\pi\,t$ . Where 't' is the sec and 'V' is in volts. Then
Updated On: Jul 7, 2022
- The peak voltage of the source is 100 V
- The peak voltage of the source is $100 / \sqrt2$
- The peak voltage of the source is 25 V
- The frequency ofthe source is 50 HZ
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The Correct Option is C
Solution and Explanation
$V = 50 \times 2 \, \sin \, 100 \pi \, t \cos \, 100 \pi \, t = 50 \sin 200 \pi t $
$\Rightarrow \, \, V_0 = 50 \, Volts$ and $\nu =100 \, Hz$
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Concepts Used:
AC Voltage
When voltage changes its direction after every half cycle is known as alternating voltage. The current flows in the circuit at that time are known as alternating current. The alternating current(AC) follows the sine function which changes its polarity concerning time. Most of the electrical devices are operating on the ac voltage.
