Question

The voltage gain of a transistor in common emitter configuration is 160. The resistances in base and collector sides of the circuit are 1k\( \Omega \) and 4k\( \Omega \), respectively. If the change in base current is 100\( \mu \)A, then the change in output current is

• A. \( 4 \text{ mA} \)
• B. \( 4 \mu A \)
• C. \( 40 \text{ mA} \)
• D. \( 40 \mu A \) \bigskip

Hint:

Remember that current gain in common emitter configuration is directly proportional to the change in base current.

Answer 1

The Correct Option is A

The voltage gain in a common emitter transistor can be related to the current gain through the following relation: \[ \Delta I_{out} = \text{Voltage Gain} \times \Delta I_{in} \] \bigskip Step 1: The voltage gain is given as 160, and the change in the base current is \( 100 \mu A \). The change in the output current is therefore: \[ \Delta I_{out} = 160 \times 100 \mu A = 4 \text{ mA} \] Thus, the correct answer is \( 4 \text{ mA} \). \bigskip