Step 1: Find the magnitudes of the vectors
Compute the magnitudes: \[ |\vec{a}| = \sqrt{2^2 + (-1)^2 + 1^2} = \sqrt{6}, \,\] \[|\vec{b}| = \sqrt{1^2 + (-3)^2 + (-5)^2} = \sqrt{35}, \,\]\[ |\vec{c}| = \sqrt{(-3)^2 + 4^2 + 4^2} = \sqrt{41}. \]
Step 2: Check for right angle using dot products
Calculate \( \vec{a} \cdot \vec{b} \), \( \vec{b} \cdot \vec{c} \), and \( \vec{c} \cdot \vec{a} \). If one is zero, the triangle is right-angled. For example: \[ \vec{a} \cdot \vec{c} = (2)(-3) + (-1)(4) + (1)(4) = -6 - 4 + 4 = 0. \]
Step 3: Conclude the type of triangle
Since \( \vec{a} \cdot \vec{c} = 0 \), the triangle is right-angled.
An instructor at the astronomical centre shows three among the brightest stars in a particular constellation. Assume that the telescope is located at \( O(0,0,0) \) and the three stars have their locations at points \( D, A, \) and \( V \), having position vectors: \[ 2\hat{i} + 3\hat{j} + 4\hat{k}, \quad 7\hat{i} + 5\hat{j} + 8\hat{k}, \quad -3\hat{i} + 7\hat{j} + 11\hat{k} \] respectively. Based on the above information, answer the following questions: