Question:
The value of \(\int\limits_C \frac{\sin\pi z^2+\cos\pi z^2}{(z-1)(z-2)}dz\), where C is the circle |z|=3 is
The value of \(\int\limits_C \frac{\sin\pi z^2+\cos\pi z^2}{(z-1)(z-2)}dz\), where C is the circle |z|=3 is
Updated On: Mar 21, 2024
- 4πi
- 8πi
- 2πi
- πi
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The Correct Option is A
Solution and Explanation
The correct answer is(A): 4πi
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