Question:
The value of the integral
\(\int\frac{e^x(x^2+1)}{(x+1)^2}\ dx=\)
The value of the integral
\(\int\frac{e^x(x^2+1)}{(x+1)^2}\ dx=\)
\(\int\frac{e^x(x^2+1)}{(x+1)^2}\ dx=\)
Updated On: Sep 15, 2024
- \(e^x\log(\frac{x-1}{x+1})+c\)
- \(e^x\log(\frac{x+1}{x-1})+c\)
- \(e^x(\frac{x+1}{x-1})+c\)
- \(e^x(\frac{x-1}{x+1})+c\)
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The Correct Option is D
Solution and Explanation
The correct option is (D) : \(e^x(\frac{x-1}{x+1})+c\).
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