Question

The value of the integral
$\int\frac{e^x(x^2+1)}{(x+1)^2}\ dx=$

• A. $e^x\log(\frac{x-1}{x+1})+c$
• B. $e^x\log(\frac{x+1}{x-1})+c$
• C. $e^x(\frac{x+1}{x-1})+c$
• D. $e^x(\frac{x-1}{x+1})+c$

Answer 1

The Correct Option is D

The correct option is (D) : $e^x(\frac{x-1}{x+1})+c$.