We are tasked with finding the value of the limit:
\[
\lim_{x \to \infty} \left( \frac{\pi}{2} - \tan^{-1} x \right)^{1/x}.
\]
Step 1: Behavior of \( \tan^{-1} x \) as \( x \to \infty \).
We know that as \( x \to \infty \), the arctangent function behaves as:
\[
\tan^{-1} x \to \frac{\pi}{2}.
\]
So, the expression \( \frac{\pi}{2} - \tan^{-1} x \) approaches zero as \( x \to \infty \).
Step 2: Substituting into the limit.
Substitute \( \frac{\pi}{2} - \tan^{-1} x \) into the limit expression:
\[
\lim_{x \to \infty} \left( \frac{\pi}{2} - \tan^{-1} x \right)^{1/x}.
\]
We now need to examine the behavior of the quantity \( \left( \frac{\pi}{2} - \tan^{-1} x \right)^{1/x} \) as \( x \to \infty \). Since \( \frac{\pi}{2} - \tan^{-1} x \) approaches 0, we are dealing with the limit of a form similar to \( 0^{1/x} \).
Step 3: Simplifying the expression.
For very large \( x \), \( \frac{\pi}{2} - \tan^{-1} x \) can be approximated by the following expansion:
\[
\frac{\pi}{2} - \tan^{-1} x \approx \frac{1}{x}.
\]
Thus, the expression becomes:
\[
\lim_{x \to \infty} \left( \frac{1}{x} \right)^{1/x}.
\]
This simplifies to:
\[
\lim_{x \to \infty} x^{-1/x}.
\]
We know that \( x^{-1/x} \) approaches 1 as \( x \to \infty \).
Step 4: Conclusion.
Therefore, the value of the limit is 1, and the correct answer is (b).