Question:

The value of \( \lim_{x \to \infty} \dfrac{x \ln(x)}{1 + x^2} \) is:

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When evaluating limits, consider the growth rates of terms in the numerator and denominator. The term with the higher power of \( x \) will dominate as \( x \to \infty \).
Updated On: Dec 20, 2025
  • 0
  • 1.0
  • 0.5
  • \( \infty \)
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The Correct Option is A

Solution and Explanation

We are asked to evaluate the limit: \[ \lim_{x \to \infty} \frac{x \ln(x)}{1 + x^2}. \] As \( x \to \infty \), the denominator grows much faster than the numerator because \( x^2 \) dominates \( \ln(x) \). Therefore, the limit of this expression as \( x \to \infty \) is 0. 

Final Answer: \[ \boxed{0}. \]

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