Question:
The value of acceleration due to gravity at the surface of earth
The value of acceleration due to gravity at the surface of earth
Updated On: Apr 29, 2024
- is maximum at the poles
- is maximum at the equator
- remains constant everywhere on the surface of the earth
- is maximum at the international timeline
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The Correct Option is A
Solution and Explanation
Value of acceleration due to gravity is
$g=\frac{GM}{R^{2}}$
At poles $R$ is minimum and at equator $R$ is maximum, hence $g$ is maximum at poles.
$g=\frac{GM}{R^{2}}$
At poles $R$ is minimum and at equator $R$ is maximum, hence $g$ is maximum at poles.
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].