Question:
The unpaired electron in $ Ni(CO)_{4} $ is
The unpaired electron in $ Ni(CO)_{4} $ is
Updated On: Jun 14, 2022
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The Correct Option is D
Solution and Explanation
In $N i(C O)_{4}$, there is no unpaired electron.
It is diamagnetic.
Oxidation state of $N i$ in $\left[N i(C O)_{4}\right]$
complex compound is zero.
$N i=3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $Ni$
$\left[N i(C O)_{4}\right]$
It is diamagnetic.
Oxidation state of $N i$ in $\left[N i(C O)_{4}\right]$
complex compound is zero.
$N i=3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $Ni$
$\left[N i(C O)_{4}\right]$
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.