Step 1: Understanding the conversion of benzene diazonium chloride to biphenyl
The conversion of benzene diazonium chloride to biphenyl (
C6H5−C6H5) involves two key reactions:
1. Sandmeyer Reaction:
- This reaction replaces the diazonium group (-
N2+) with a halogen (Cl, Br, I) using a copper(I) halide catalyst (
CuX).
- In this case, benzene diazonium chloride reacts with CuCl to form chlorobenzene (
C6H5Cl).
2. Fittig Reaction:
- This reaction is similar to the Wurtz reaction but involves aryl halides.
- Two molecules of chlorobenzene undergo coupling in the presence of sodium metal in dry ether, forming biphenyl (
C6H5−C6H5).
Step 2: Examining the given options
- Option 1 (Swarts, Fittig) → Incorrect, as Swarts reaction is used for halogen exchange and is not involved in this conversion.
- Option 2 (Gattermann, Swarts) → Incorrect, as Gattermann reaction involves formylation of benzene derivatives, which is unrelated to biphenyl formation.
- Option 3 (Sandmeyer, Wurtz) → Incorrect, as Wurtz reaction applies to alkyl halides, not aryl halides.
- Option 4 (Sandmeyer, Fittig) → Correct, as these two reactions successfully convert benzene diazonium chloride to biphenyl.
Step 3: Conclusion
Since the correct sequence involves Sandmeyer reaction (for halogen substitution) followed by the Fittig reaction (for biphenyl formation), the answer is Option (4).