Step 1: Condition for achromatic combination.
Achromatic doublet means no chromatic aberration.
So dispersion produced by one lens must cancel dispersion of the other lens.
Step 2: Use achromatic condition.
If \(P_1, P_2\) are powers and \(\omega_1, \omega_2\) are dispersive powers, then:
\[
P_1\omega_1 + P_2\omega_2 = 0
\]
Step 3: Match with options.
This clearly means that the sum of (power × dispersive power) of both lenses must be zero.
Final Answer:
\[
\boxed{P_1\omega_1 + P_2\omega_2 = 0}
\]