Question:

The two ends of a train moving with constant acceleration pass a certain point with velocities u and v. The velocity with which the middle point of the train passes the same point is

Updated On: Jul 29, 2024
  • $(u + v)/2$
  • $(u^2 + v^2)/2$
  • $\sqrt{(u^2 + v^2)/2}$
  • $\sqrt{u^2 + v^2}$
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The Correct Option is C

Solution and Explanation

Let the length of train is s, then by third equation of motion, $v^2 = u^2 + 2a \times s$ ....(1) Where v is final velocity after travelling a distance s with an acceleration a & u is initial velocity as per question Let velocity of middle point of train at same point is v', then $(v')^2 = u^2 + 2a \times (s/2)$ ....(2) By equation (1) & (2), we get $v' = \sqrt{\frac{v^2 + u^2}{2}}$
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Concepts Used:

Speed and Velocity

The rate at which an object covers a certain distance is commonly known as speed.

The rate at which an object changes position in a certain direction is called velocity.

Difference Between Speed and Velocity:

Difference Between Speed and Velocity

Read More: Difference Between Speed and Velocity